0=2x^2+4x+26

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Solution for 0=2x^2+4x+26 equation: 



0=2x^2+4x+26

We move all terms to the left:

0-(2x^2+4x+26)=0

We add all the numbers together, and all the variables

-(2x^2+4x+26)=0

We get rid of parentheses

-2x^2-4x-26=0

a = -2; b = -4; c = -26;
Δ = b2-4ac
Δ = -42-4·(-2)·(-26)
Δ = -192
Delta is less than zero, so there is no solution for the equation

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